How to effectively Bypass a component : On/Off

I'm trying to figure out what the best and most efficient way is, to bypass a component.

Example, somewhere at the end of a line there is a Blur component (slow component).
Now I want the user be able to choose between going through the Blur component and bypassing the Blur component. With a switch between the Blur and the signal before the Blur it can be done, but the rendering time is equal in both cases, as the Blur is rendered anyway, even if not used after the Blur itself. I want to be able to bypass the Blur and at the same time not losing the rendering time for the Blur, as it is not used in 'bypass' configuration. I think I would need a switch with 2 inputs and one output, but I'am afraid this component does not exist yet

In addition : is a subtree, that has no connection to the result (so a dead end), being rendered and adding up to the render time?

Thanks rachelduim (Nederlandse naam? Ik zit (ook?) in Nederland).

I will run tests tomorrow, it's already getting quite late.
I downloaded your test filter and how nice that it installs right away into FF. Really neat, as many other things in FF, e.g. the easy connection of the wires. Even in quite zoomed out view, it still works like a charm. About other things, I am quite surprised that they are missing . . . or of course, that I haven't found them yet
I'll keep you posted of my findings.

In my experience, there's definitely some (pre)processing happening for unconnected subtrees. They won't be fully rendered so the slowdown isn't huge, but you shouldn't leave heavy subtrees laying around even if not connected.

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emme wrote : but you shouldn't leave heavy subtrees laying around even if not connected.

Right I understand. What I actually meant: a heavy subtree that connects to a switch on input 2, but the Switch being in position 1. I misnomered that as 'that has no connection to the result (so a dead end).'

rachelduim : Yes 'duim' means 'thumb' allright. And Rachel is a Dutch name as well as English

Thanks for all the help I'm getting. Really appreciate.