Ramlyn
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I don't know if this is a bug or not, but I report it anyway.
I was updating a filter. Halálra szeretlek.ffxml |
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| Posted: September 11, 2017 2:05 pm | ||
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Ramlyn
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The filter creates some polygons, colors them (with colors or images), then adds shadows to every image.
I passed the result through a free rectangle. And I get this :  |
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| Posted: September 11, 2017 2:10 pm | ||
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Ramlyn
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Something is not ok, because the result should simply add color to the Free Rectangle and not going outside it.
Instead, as you can see, the shadows are going outside. That is what happened selecting Image Bounds in the XX Anchor. I thought, wrongly, that maybe it could be solved changing the XY Anchor. Changing to Default Size, I get :  |
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| Posted: September 11, 2017 2:16 pm | ||
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Ramlyn
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I tried to bring all components to Default Size or to Image Bounds, but same result.
Then, when we have a non squared picture and we use a filter that uses a Free Rectangle with coordinates 0,0,1,1 among its components...... - In case we sel ect "Default Size", the Free Rectangle starts fr om the top left corner 0,0 and ends in 1,1 , inside our picture. - But if we select "Image Bounds", what does it do? In my case..... it is not squared anymore. I don't understand it. I explain why. |
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| Posted: September 11, 2017 2:32 pm | ||
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Ramlyn
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If its size was my default result size, I should not see the shadows on the sides.
It should appear as follows :  |
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| Posted: September 11, 2017 2:33 pm | ||
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Ramlyn
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If instead it considered the size of the non squared image, its center should move too.
The result should be something like this :  |
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| Posted: September 11, 2017 2:37 pm | ||
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Ramlyn
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So......
I don't really get why the SQUARED rectangle centers the non squared image, but it keeps the black shadows that are outside of the square. Doing this it is not squared anymore. |
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| Posted: September 11, 2017 2:41 pm | ||
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Ramlyn
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Here is the result setting the Free Rectangle to 0,0,1,1 size and Image Bound.
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| Posted: September 11, 2017 5:15 pm | ||
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Ramlyn
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Here is instead the result simply increasing X to 1.35
Free Rectangle 0,0,1.35,1 and Default Size.  |
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| Posted: September 11, 2017 5:20 pm | ||
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Ramlyn
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Does it mean that, no matter what is the picture shape, the Free Rectangle always starts from the top left corner? And also that only the bigger coordinate of the picture is considered and the smaller is ignored, even if doing so, it goes outside the picture border?
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| Posted: September 11, 2017 5:28 pm | ||
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